Kamil Założenia x 2 − y 2 różne od zera Stąd x różne o y i różna od −y Dziękuję bardzoN) y = (x 4) 2 1 przesuwam wykres funkcji y = x 2 o 4 jednostki w lewo wzdłuż osi x i o 1 jednostkę w dół wzdłuż osi y x 2 1 0 1 2 y = x 2 4 1 1 1 4 2) Podaj współrzędne wierzchołka paraboli, będącej wykresem funkcji f, jeśliAnswer 6 x3 7 x2 y 12 x y2 5 y3 Apply Multiplicative Distribution Law 2 x 3 x2 2 x y 5 y2 y 3 x2 2 x y 5 y2Apply Multipli
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X+y=-2 x^2+y^2=100
X+y=-2 x^2+y^2=100-Find the absolute maximum and minimum values of f(x, y) = 2 2x 2y – x 2 – y 2 on triangular plate in the first quadrant, bounded by the lines x = 0, y = 0 and y = 9 – xDany jest okrąg o równaniu x^2 4x y^2 5 = 0 daniel Dany jest okrąg o równaniu x 2 − 4x y 2 − 5 = 0 i punkt P = (5,4) Napisz równanie okręgu o środku w punkcie P i
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The main integral I = ∫ x2 − y2 (x2 y2)2 dx can be solved using a tan substitution x = ytanθ dx = ysec2θdθ So that I = ∫y2(tan2θ − 1) y4sec4θ ysec2θdθ = 1 y∫tan2θ − 1 sec2θ dθ = 1 y∫sin2θ − cos2θdθ = − 1 y∫cos2θdθ = − 1 y1 2sin2θ h(y) = − 1 2y 2tanθ 1 tan2θ h(y) = − 1 2y 2(y / x) 1 (yAprende en línea a resolver problemas de ecuaciones diferenciales paso a paso Resolver la ecuación diferencial dy/dx3*x^2*y=x^2 Agrupar los términos de la ecuación diferencial Mover los términos de la variable y al lado izquierdo, y los términos de la variable x del lado derecho de la igualdad Simplificar la expresión \frac{x^2}{x^2}dxPigor , a po kolei np tak w zbiorze punktów (par) (x,y)=?
With multiplying factor x^ay^b in equation and finding a and b the integrating factor is \mu=\color {blue} {\dfrac {y} {x}} Alternative method Drop a x of equation, then \left (2x \frac {1} {y^ 2}\right)dx \left (\frac {x^2} {y}\frac {x} {y^3}\right)dy = 0Płaszczyzny ograniczają obszar całkowania, który możemy zapisać tak \V=\{(x,y,z)\in \mathbb{R}^3 z\ge0,\ z\le x^2y^22,\ x^2y^2\le 4 \}\ Czyli mamy doSubresultants(x^2 y^2, y^21, y) groebner basis({x^2 y^2, y^2 x^2}, {x, y}) div {x^2 y^2, y^2 x^2}
Answer 2 x y x y Rewrite the term 2 x2 x y 2 x y y2Regroup terms into two proportional parts 2 x2 x y 2 Solve the system of equations by using the method of cross multiplication 5/xy 2/x− y 1 = 0, 15/xy 7/x− y – 10 = 0 asked Jun 23 in Linear Equations by Hailley (334k points) linear equations in two variables;Suppose the curves are x = y2 and x = 4 y2 and and you want to find points on the two curves with the same yvalue Then substitute y 2 from the first equation into the second to obtain x = 4 x So to achieve the same yvalue the xvalue on the second curve must be (minus) 4 times the xvalue on the first curve x = 4y2 and x = y2
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorClick here👆to get an answer to your question ️ If 2^x 2^y = 2^x y , then dydx is equal to
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Subtract x^ {2} from both sides of the equation Subtracting x^ {2} from itself leaves 0 Divide x, the coefficient of the x term, by 2 to get \frac {x} {2} Then add the square of \frac {x} {2} to both sides of the equation This step makes the left hand side of the equation a perfect square Square \frac {xRearrange like terms to the same side of the equation \begin{equation}\begin{cases} y = 7 2 x\\y^{2} x (x y) = 11\end{cases}\end{equation} Divide both sides of the equation by the coefficient of variable \begin{equation}\begin{cases}y = 7 2 x\\y^{2} x (x y) = 11\end{cases}\end{equation} Substitute one unknown quantity into the elimination ( 7 2 x)^{2} x (x 7 2 xRozwiązać całkę ∫∫ydxdy w podanym regionie D={(x,y)∈R^2 x≥1, x^2 y^2 ≤2} Michał Rozwiązać całkę ∫∫ydxdy w podanym regionie D={(x,y)∈R 2x≥1, x 2 y 2 ≤2} Mój pomysł na zadanie jest to zamiana na współrzędne biegunowe D = { 1
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So take our first equation xy =2, and subtract x from both sides, like this y = 2x, now from here we take that expression for y and subsitute it into our second equation So out second equation x^2 2y = 12, becomes x^2 2(2x) = 12, expanding out the brackets we get x^2 2x 4 = 12, and take away 12 from both sides which will give us x^2 2 8 = 0Y= s 1 Cex2 1 Gdy xy0 y = y2 ln x, to stosujemy podstawienie zy = 1, a więc z0 = −y0 y2 Po wykonaniu podstawienia dostajemy równanie liniowe niejednorodne −xz0z= ln x takie, że całką ogólną jego części jednorodnej z= xz0 jest funkcja z(x) = Cx Stosujemy metodę uzmienniania stałej, kładąc z= C(x)x, a następnie wyliczamy z0= C0x C Skoro Z ln x x2 dx= ln x −x Z dx x2Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music
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